I think you can use db.collection.distinct(fields,query). You will be able to get the distinct values in your case for NetworkID. ... <看更多>
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I think you can use db.collection.distinct(fields,query). You will be able to get the distinct values in your case for NetworkID. ... <看更多>
Returns the distinct values for a given field. ... Legacy (in MongoDB.Driver. ... public virtual IEnumerable<BsonValue> Distinct( string key ). ... <看更多>
MongoDB Aggregation Framework way for "select count (distinct fieldName) from someTable" for large collections - gist:3241616. ... <看更多>
Tutorial MongoDB 4.2 Parte 8 - Count, Distinct y Limit ... Explicao como ocupar operaciones sobre consultas ... ... <看更多>
I've been trying to improve the performance of queries running a "distinct" operation using the MongoDB API. These are relatively slow, ... ... <看更多>
I believe the best way to achieve that is by using the aggregation framework: db.collection.aggregate( {$unwind : "$ccNameCount"}, ... ... <看更多>